25=b^2/5

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Solution for 25=b^2/5 equation: 


b in (-oo:+oo)

25 = (b^2)/5 // - (b^2)/5

25-((b^2)/5) = 0

-1/5*b^2 = -25 // : -1/5

b^2 = 125

b^2 = 125 // ^ 1/2

abs(b) = 5*5^(1/2)

b = 5*5^(1/2) or b = -(5*5^(1/2))

b in { 5*5^(1/2), -(5*5^(1/2)) }

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